已知2的a次方=3,4的b次方=5,8的c次方=7,求8的a+c—2b次方,要过程_百度...
http://zhidao.baidu.com/question/527087288.html?fr=search&word=%23%26%2365533%3B%26%2365533%3B%26%2365533%3B8VSP%26%2365533%3BC%1F%26%2365533%3B%2A%26%2365533%3B&ie=gbk ——百度知道
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答:因为4的b次方=5,所以2^2b=5 因为8的c次方=7,所以2^3c=7 所以8的a+c—2b次方=8^a*8^c/8^2b=27*7/125=189/125